Physics, asked by Pralabh5010, 8 months ago

A force acts on a 30 gm particle in such a way that the position
of the particle as a function of time is given by x = 3t – 4t²
+ t³, where x is in metres and t is in seconds. The work done
during the first 4 seconds is
(a) 576 mJ (b) 450 mJ
(c) 490 mJ (d) 530 mJ

Answers

Answered by rohithkumarr1792004

1

Answer:

I think 576 is the answer

Answered by nonigopalbarman857

3

Answer:

450mj

follow me......

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