Question

A force acts on a 30 gm particle in such
a way that the position of the particle
as a function of time is given by x = 35
– 4t2 +t3, where x is in metres and t is
in seconds. The work done during the
first 4 seconds is​

Answer 1

The work done during the first 4 seconds is: ... particle as a function of time is given, x=3t−4t2 +t3. where x is in meters and t is in second.

The mass is 30 g or 0.03 kg and the position of the particle is x = 3t - 4t2 + t3 . The velocity is given as, dxdt = 3 - 8t + 3t2 The acceleration ...