Question

A force acts on a 3g particle in such a way that the position of the particle as a function of time is given by x=3t-4t ^2 +t^3 where x is in meters and t is in seconds. The work done during the first 4 sec.

Answer 1

Given force = 3g
1g = 1/1000kg
3g = 3/1000 kg
Displacement = 3t-4t^2+t^3
First 4 sec, work = force *displacement
3/1000*12 = 9/250kgms