Question

A force acts on a body at rest of mass 200 kg for 10 sec. When the force stops acting, the body moves through a distance 100 m with a constant velocity in 5 sec. Calculate the force​

Answer 1

Explanation:

ANSWER

Let initial velocity = u = 0

Using equation of motion, v = u +at = 0+a(10) = 10a

distance in 10 sec = s = vt = 100=10a(5)

a=2m/s

2

∴v=10a=10(2)m/s=20m/s

Answer 2

Let initial velocity = u = 0

Using equation of motion, v = u +at = 0+a(10) = 10a

distance in 10 sec = s = vt = 100=10a(5)

a=2m/s

2

∴v=10a=10(2)m/s=20m/s

Answer By

TERA BHAI GOLU