Question

A force acts on a body for 5s changes its momentum from 16.0kgm/s to 21kgm/ . What is the magnitude of the force?

Answer 1

Answer:

The magnitude of the force which acts on this body is 1 newton.

Explanation:

Given,

t = 5 second

Pi = 16 kgm/s

Pf = 21 kgm/s

Then,

∆P = Pf - Pi

∆P = (21 - 16) kgm/s

∆P = 5 kgm/s

F = ma

F = m∆v/t

F = ∆P/t

F = (21 - 16) / 5 newton

F = 5/5 newton

F = 1 newton

Here,

F is the force of this body.

m is the mass of body.

∆v is the change in velocity of body.

a is the acceleration of the body.

t is the time .

P is the momentum of the body.

Pi is the initial momentum of the body.

Pf is the final momentum of the body.

Hence,.

The magnitude of the force which acts on this body is 1 newton.