a force acts on a body of mass 10 kg if the velocity of the body changes from 5 ms-1 - 3 ms - 1, then what is the work done by the force on the body?
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A force acts on a body of mass 10 kg if the velocity of the body changes from 5 m/s to 3 m/s, then what is the work done by the force on the body?
Answer:
Work = Change in Kinetic energy
= 0.5mv² - 0.5mu²
= [0.5 × 10 kg × (3 m/s)²] - [0.5 × 10 kg × (5 m/s)²]
= 45 J - 125 J
= -80 J
Work done by force is -80 Joule
Here negative sign indicates that Force is acting in the direction opposite to the motion of body.
A force acts on a body of mass 10 kg if the velocity of the body changes from 5 m/s to 3 m/s, then what is the work done by the force on the body?
Answer:
Work = Change in Kinetic energy
= 0.5mv² - 0.5mu²
= [0.5 × 10 kg × (3 m/s)²] - [0.5 × 10 kg × (5 m/s)²]
= 45 J - 125 J
= -80 J
Work done by force is -80 Joule
Here negative sign indicates that Force is acting in the direction opposite to the motion of body.
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Answer:
mass= 10kg
u=5m/s
v=3m/s
work=1/2m(v^2-u^2)
= 1/2×10( 3^2-5^2)
= 5×9-25
= 5×-16
= -80J
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