Question

A Force acts on a body of mass 10kg. If the velocity of the body changes from 5m/s to 3m/s.Then what is the work done by the force n

Answer 1

$\huge \boxed{ \mathcal{Hello \: Friend }} \:$

$Here is your answer:-$

$According \: to \: the \: work \: energy \\ \: theorem, \\ \\ For \: work \: done \: W \: and \: kinetic \\ \: energy \: ke$

$W= \triangle \: ke$

$W=ke(f)-ke(i)$

$=Mv(f)^2÷2 - Mv(i)^2÷2 \:$

$={M(v(f)^2 - v(i)^2)}÷2 \:$

$={10(3^2 -5^2)}÷2 \:$

$= \frac{10(9 - 25)}{2}$

$= \frac{10 \times ( - 16)}{2}$

$=-80 \: joules \:$

As the work is negative in value means that the work is done by the body and it is of 80 joules.

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Answer 2

Answer:

Use Work Energy Theorem