A force acts on a body of mass 200g.the velocity of the body changes from 15m/s to 25m/s in 2.5s.what is magnitude of the force, assuming the force to be constant?
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Answered by
4
Given:
m=200g
=200 into 10^-3 kg
=0.2 kg
u=15m/s
v=25m/s
t=2.5s
According to the given data we can impliy the formula for Force as:
F=ma,,,,,,,,,,,
but here we don't know acceleration.So,,,
a=v-u/t
=25-15/2.5
=10/2.5
=4
Now we can substitute acceleration in force formula:
F=ma
=0.2 into 4
=0.8 N
m=200g
=200 into 10^-3 kg
=0.2 kg
u=15m/s
v=25m/s
t=2.5s
According to the given data we can impliy the formula for Force as:
F=ma,,,,,,,,,,,
but here we don't know acceleration.So,,,
a=v-u/t
=25-15/2.5
=10/2.5
=4
Now we can substitute acceleration in force formula:
F=ma
=0.2 into 4
=0.8 N
Answered by
0
Answer:
=0.8 N
Explanation:
Given:
m=200g
=200 into 10^-3 kg
=0.2 kg
u=15m/s
v=25m/s
t=2.5s
According to the given data we can impliy the formula for Force as:
F=ma,,,,,,,,,,,
but here we don't know acceleration.So,,,
a=v-u/t
=25-15/2.5
=10/2.5
=4
Now we can substitute acceleration in force formula:
F=ma
=0.2 into 4
=0.8 N
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