Question

A Force acts on a body of mass 20g and causes one body to move with acceleration of 60.0ms-⁴.Calculate the force acting on the body.

Answer 1

Answer:

Initial velocity of the body = 0 ms^{-1}s

−1

Final velocity of the body = \frac{distance}{time}

time

distance

= \frac{60m}{5s}

5s

60m

= 12ms^{-1}12ms

−1

Now We know,

Acceleration = \frac{FinalVelocity-InitialVelocity}{timetaken}

timetaken

FinalVelocity−InitialVelocity

= \frac{v-u}{t}

t

v−u

= \begin{gathered}\frac{12ms^{-1}}{6s}\\\\=2ms^{-2}\end{gathered}

6s

12ms

−1

=2ms

−2

By Newton's second law of motion,

F = ma

= \begin{gathered}20kg*2ms^{-2} \\\\= 40N\end{gathered}

20kg∗2ms

−2

=40N

Thus the magnitude of Force is 40N.