Question

A force acts on a body of mass 3 kg such that it's velocity changes from 4 ms^-1 to 10ms^-1. The change in momentum of the body is :

Answer 1

Explanation:

p=m(∆v)

∆v=vf-vi

p=3*(10-4)

p=18kgms^-1

Answer 2

W=ke(f)-ke(i)

=Mv(f)^2÷2 - Mv(i)^2÷2

= 3*(10)^2-3*(4)^2

= 300-48

= 252 N