Physics, asked by verma5155, 10 months ago

A force acts on a body of mass 5kg and changes its velocity from 8m/s to 12m/s in 4s. Then magnitude of force is

Answers

Answered by rahulmaddheshiya5012
62

Answer:

5 newton

Explanation:

We know that rate of change in magnitude is directly propartional to applied ForceInitial momentum = 8*5= 40kgm/s

Final momentum= 12*5= 60kgm/s

then, change in momentum = final momentum - initial momentum = 60-40=20 kgm/s

applied Force= 20/4= 5 newton

Answered by sonuchauhan16016
4

5 newton is right answer

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