Question

A force acts on a mass of 16 g for 3 s and then ceases to act. What the magnitude of the force?​

Answer 1

Answer:

144 dyn

Explanation:

While covering the distance of 81 cm, there was no external force on the body and therefore it must have covered this distance with a uniform velocity v, generated when the force was acting on the body.

s = vt or, v = `(s)/(t) = (81)/(3) = 27 " cm " cdot s^(-1)`

If the acceleration on the body due to force was a then

`" "` v = u + at or, 27 = 0 + a`xx`3 or, a = 9 cm `cdot s^(-2)`

`therefore" "` Applied force, F = ma = 16 `xx` 9 = 144 dyn.

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