Question

a force acts on a particle mass 200 times the velocity of the particle changes from 15 meter per second 25 meter per second in 2.5 seconds assuming the force be constant the magnitude of force is

Answer 1

Hii

as given in ur question

m=200×v-u
m=200(25-15)
m=200×10
m=2000

Now, magnitude of force is

F=ma
F=2000×a

and a= v-u/t
a=25-15/2.5

a= 4

F= 2000×4
F=8000 N