Question

a force acts on a particle of mass 200 g the velocity of the particle changes from 15 MS - 1 to 25 MS - 1 in 2.5 seconds assuming the first to be constant the magnitude of force is

Answer 1

F=?
F=m×(v-u)/t

200g=0.2kg

0.2×(25-15)/2.5
F=0.8N or 0.8 kg.m/s×m/s