Question

a force acts on a particle of mass 200 grams the velocity of the particle changed from 15 MS power minus 25ms1 for -1 in 2.5 seconds resuming the force to be constant the magnitude of the force is​

Answer 1

Explanation:

according to Newton 2nd law

Answer 2

it is given that initial velocity(u)=15m/s
final velocity(v)=25m/s
time(t)=2.5 sec
mass(m)=0.2kg
to find:force(f)
sol: since,f=ma -(here,a is acceleration)
and a=v-u/t i.e. a=25-15/2.5
therefore,a=4m/s^2
therefore,f=m×a i.e. f=0.2 × 4=0.8newton