Question

A force acts on a particle of mass 200g. The velocity of the particle changes from 15 ms 1 to 25 ms -1 in 2.5 s. Assuming the force to be constant, the magnitude of force is

Answer 1

Answer:

m = 200 g = 200 ÷ 1000 = 0.2 Kg

u = 15 m/s

v = 25 m/s

t = 2.5 s

By Newton's 2nd law of motion,

F

= m(v-u)/t

= (0.2)(25-15)÷(2.5) N

= 0.2 × 10 ÷ 2.5 N

= 0.8 N (Answer)

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