Question

a force acts on a particles of mass 200g. the velocity of the particle changes from 15m/s to 25m/s in 2.5s.assuming the force to be constant,its magnitude is

Answer 1

Answer:

0.8 Newton

Explanation:

Second law of motion,

F = d(mv) /dt

Mass = 0.2 kg

Change in velocity = 10 m/s

Time = 2.5 secs

Force = 0.2(25-15)/2.5 = 0.8

Answer 2

Answer:

0.8N

Explanation:

Mass= 200g =0.2kg

Mass= 200g =0.2kgu = 15m/s

Mass= 200g =0.2kgu = 15m/sv = 25m/s

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 sec

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5 = 4m/s^2

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5 = 4m/s^2Now to find the magnitude

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5 = 4m/s^2Now to find the magnitudeForce(magnitude) = mass × acceleration

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5 = 4m/s^2Now to find the magnitudeForce(magnitude) = mass × acceleration = 0.2 × 4

Mass= 200g =0.2kgu = 15m/sv = 25m/st = 2.5 seca = v-u t =25-15 2.5 = 10 2.5 = 4m/s^2Now to find the magnitudeForce(magnitude) = mass × acceleration = 0.2 × 4 = 0.8 N