Question

A force acts on an object of mass 10kg for 3s. It increases the velocity of the object from 3m/s to 9m/s.
(a) Find the magnitude of the force applied.
(b) If this force is applied for 5s, what will be the final velocity?​

Answer 1

Given,

mass=5kg

t
1
​
=2s

Initial velocity u=3m/s

Final velocity v=7m/s

t
2
​
=5s

So,

Let the Force be F

Let the acceleration be a

So,

a=
t
(v−u)
​
=
2
(7−3)
​
=2m/s
2


So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s


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