Question

a force applied on an object of mass 50 gram changes its velocity from 5 metre per second to 8 metre per second into second calculate the change in momentum of the object

Answer 1

Answer:

Given,

Mass.m = 20 kg.

Initial velocity, u=5m/s

Final velocity, v=2m/s

Work done = change in K.E.

W=

2

1

.mv

2

−

2

1

mv

2

=

2

1

m(v

2

−u

2

)

=

2

1

.20(2

2

−5

2

)

=

2

1

.20(4−25)

=−10.(21)

=−210J

∴ Here, the negative sign implies the retarding

nature of the applied force.

Step-by-step explanation:

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