Question

A force changes the velocity of a box of mass 2 kilograms from 2 metre per second to 3 m/seconds in 3sec. Find the acceleration and the magnitude of force

Answer 1

Data --- m = 2kg ; u = 2m/s ; v = 3m/s

t = 3sec

f = ma = m(v-u)/t = 2(3-2)/3 = 0.67N

a = (v-u)/t = (3-2)/3 = 1/3 m/s2

$a \: = 0.3ms {}^{ - 2 }$