Question

a force changes the velocity of a box of mass 2kg from 2m/s to 5m/s in 34. find force and work

Answer 1

Let final velocity =v=5m/s
Initial velocity =u=2m/s
Total time=t=34 seconds
Acceleration =
$a = \frac{v - u}{t} = \frac{5 - 2}{34} = 0.088 \frac{m}{ {s}^{2} }$
Force=
$f = m \times a = 2 \times 0.088 = 0.176$
Hence, force of 0.176 Newton is applied..
Displacement of body
$s = ut + 0.5 \times a {t}^{2} \\ \: \: \: \ \\ \: \: \: = 2 \times 34 + 0.5 \times 0.088 \times {34}^{2} \\ \: \: \: = 118.864m$
Hence work=
$w = f \times s \\ = 0.176 \times 118.864 \\ = 20.92 \: newtom \times m$