Question

A force F= (0.5x + 12)N acts on a particle .If x is in meters ,calculate the work done by the force during the displacement of the particle from x = 0 to x = 4


128J


52J


80J


64J

Answer 1

Answer:

dW=F.dx

Explanation:

Integrating F

0.5x^2/2+12x and then put values of x we get

4+48=52