Question

A force F = (10 + 0.50 x) acts on a particle in x direction, where F is in
newton and x is in metre. Find the work done by this force during a displacement from x = 0 to x = 2 m.
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Answer 1

Answer:

As the force is variable, we shall find the work done in a small displacement x to x+dx and then integrate it to find the total work. The work done in this small displacement is <br>

<br> Thsu,

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Explanation:

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