Physics, asked by amanpatel26335, 2 days ago

A force F = (10+10y)j acts on a particle moving in y direction, where Fis in N and y in metre. The work done by this force to move the particle from y = 0 to y = 2 m is

Answers

Answered by balajijanakiraman139

0

=(10+10)

Explanation:

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