A force F= 10 N accelerates a box over a displacement 2 m. The floor is rough and exerts a friction force 1 = 2 N.
A) Calculate the positive work done by force F
Answers
Answered by
1
Answer:
20 J
Explanation:
As the work done is given by the dot product of the Force and displacement
W = Fs cosФ
Where Ф is the angle between the force and displacement.
Work done by the applied force W = Fs cos0
W= FS
W= 10×2 = 20 J
Similar questions