Question

A force F = 10 N acting on a box 1 m along a horizontal surface. The force acts at 30° angle. Determine the work done by force the work done force F.​

Answer 1

Explanation:

Given :-

Force (F) = 10 N

The horizontal force (Fx) = Fcos30°

Fx = 10(√3/2) = 5 × 1.73 = 8.65 N

Displacement (s) = 1 m

____________________________

To find :-

Work done (W) = ?____________________________

Solution :-

We have,

Work done (W) = Force × displacement

=> W = Fx × s

=> W = 8.65 × 1

=> W = 8.65 J

_____________________________

The work done is 8.65 J

_______________________[Answer ]

Answer 2

Answer:

Explanation:Given :-

Force (F) = 10 N

The horizontal force (Fx) = Fcos30°

Fx = 10(√3/2) = 5 × 1.73 = 8.65 N

Displacement (s) = 1 m

____________________________

To find :-

Work done (W) = ?____________________________

Solution :-

We have,

Work done (W) = Force × displacement

=> W = Fx × s

=> W = 8.65 × 1

=> W = 8.65 J

_____________________________

The work done is 8.65 J

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