Question

a force F=2^i+3^j+^k acts on a body and the displacement made is s=2^i+^j+^k the work done is​

Answer 1

Answer:

${1}^{?91.} xdg log( \tan(022 \beta ) )$

Answer 2

Explanation:

work done= force.displacement

W=F.S

w= 4+3+1=8 Nm