Question

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in metre.find the work done by this force during a displacement from x= 0.1 to x=2.0

Answer 1

Not sure .....hope so it will be correct!!!!!!

Answer 2

Answer:

W = 5.795 Joules

Explanation:

Given that,

Force, F = 2 + x

Work done is given by :

$W=\int Fdx$

$W=\int_{0.1}^{2} (2+x)dx$

$W=\left [2x+\dfrac{x^2}{2}  \right ]_{0.1}^2$

Using limits :

W = (4+2) - (0.2+0.005)

W = 5.795 J

Hence, this is the required solution.