Question

A force f = 20 + 10 y acts on a particle in y-direction where f is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is

Answer 1

Explanation:

work done is the dot product of force and displacement. and when force is function of displacement then, workdone is found by using the concept of integration.

• workdone = integragtion of F.ds in limits 0 to 1.

If you know how to integrate then you'll reach the following eqn . Solving it will give the results as follows.

= 20[1 - 0] + 10[1²/2 - 0²/2 ]

= 20 + 5

= 25 Joule

hence, workdone by force to move particle from 0 to 1 is 25 Joule.

Hope it helped .