Question

A force F=20+10y acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from y=0 to y=1 m is:

Answer 1

Explanation:

Answer is 25

use the formula dw=Fdy and integrate with limits

Answer 2

Question: A force F = 20 + 10y acts on a particle in y-direction where F is in Newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1m is:

Solution: Work done by variable force is,

$W=\int\limits^f_i Fdy$

Hence, $y_i =0, y_f=1m$

$W=\int\limits^1_0 (20+10y)dy= [20+\frac{10y^{2} }{y} ]^1_0 = 25J$