A force F= (21 – 10j+12K) N acts as a particle which moves along the positive Z axis. If it cove
a distance of 10 m, the work done is
(A) 40J (B) 100J (C) 120J (D) -100)
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Given F has 3 vertices on x y and z axis . Since the displacement is in z axis we have to consider z component I.e 12
Work done= F x displacement
W.D = 12 x 10=120
Work done= F x displacement
W.D = 12 x 10=120
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