Physics, asked by mdkalam9006552655, 2 months ago

A force F= (2i-2j+2k) N acts on a particle which is located at a point whose position vector = (2 i + 2j+k) m.calculate the torque, acting on the particle about the origin.​

Answers

Answered by manikdekad
3

Answer:

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Answered by abhi178
3

Given info : A force F = (2i - 2j + 2k) N acts on a particle which is located at a point whose position vector = (2i + 2j + k) m.

To find : The torque, acting on the particle about origin, is...

Solution : Torque acting on the particle about origin is given by, τ = r × F

where r is position vector of the particle, F is force acting on the particle.

here r = (2i + 2j + k) and F = (2i - 2j + 2k)

so, τ = (2i + 2j + k) × (2i - 2j + 2k)

= i(2 × 2 - 1 × -2) -j(2 × 2 - 1 × 2) + k(2 × -2 - 2 × 2)

= i(4 + 2) -j(4 - 2) + k(-4 - 2)

= 6i - 2j - 6k

Therefore the torque acting on the particle about origin is 6i - 2j - 6k.

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what is the torque of the force f=(2i-3j+4k)F, acting at the point r=(3i+2j+3k)m ABOUT THE ORIGIN (in N-m)

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