A force F= (2i-2j+2k) N acts on a particle which is located at a point whose position vector = (2 i + 2j+k) m.calculate the torque, acting on the particle about the origin.
Answers
Answer:
if8sygldtfpytdot4eou
Given info : A force F = (2i - 2j + 2k) N acts on a particle which is located at a point whose position vector = (2i + 2j + k) m.
To find : The torque, acting on the particle about origin, is...
Solution : Torque acting on the particle about origin is given by, τ = r × F
where r is position vector of the particle, F is force acting on the particle.
here r = (2i + 2j + k) and F = (2i - 2j + 2k)
so, τ = (2i + 2j + k) × (2i - 2j + 2k)
= i(2 × 2 - 1 × -2) -j(2 × 2 - 1 × 2) + k(2 × -2 - 2 × 2)
= i(4 + 2) -j(4 - 2) + k(-4 - 2)
= 6i - 2j - 6k
Therefore the torque acting on the particle about origin is 6i - 2j - 6k.
also read similar questions : What is the torque of the force F=3i-2j+4k acting at a point r=2i+3j+5k about the origin
https://brainly.in/question/16082606
what is the torque of the force f=(2i-3j+4k)F, acting at the point r=(3i+2j+3k)m ABOUT THE ORIGIN (in N-m)
https://brainly.in/question/4290254