Question

A force F = (2i + 3 j ) N produces a displacements d = (–i + 2 j ) m. Calculate the work done.

Answer 1

Answer : 4 Joules

Work :

Work done in physics can also be defined as the dot product of the Force vector and displacement vector, produced by that force.

$W = F.S$

Here,

$F = 2i + 3 j$

$S = -i + 2j$

$F.S = (2 \times ( - 1)) + (3 \times 2)$

$→W = - 2 + 6 = 4 \: J$

Hence work done = 4 Joules.