Question

A force F = (2i+ 3j– 2k) N acts on a particle acting at a point (i+ 2j– 2k). The magnitude of

torque acting on the particle is

(a) 6 Nm (b) 16 Nm (c) 3 Nm (d) 4 Nm​

Answer 1

Answer:

• (c) 3Nm is the required magnitude of torque acting on the particle .

Explanation:

⠀⠀⠀⠀According to the Question

It is given that ,

• Force ,F = (2i + 3j -2k) N
• Radius ,r = (i+ 2j -2k)

we have to calculate the magnitude of torque acting on the particle.

For calculating torque, we know that,

Torque is defined as the measure of force which cause an object to rotate about their axis .

It is a vector quantity.

$\bigstar\boxed{\bf{\overrightarrow{\tau} = \overrightarrow{r} \times\overrightarrow{F}}}\\\\\\ = \sf\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\1&2&-2\\2&3&-2\end{array}\right] \\\\\\ = \sf\hat{i} ( -4+6) - \hat{j}(-2+4) + \hat{k} (3-4) \\\\\\= \sf\hat{i} (2) - \hat{j}(2) + \hat{k} (-1) \\\\\\= \sf\;2\hat{i} - \;2\hat{j} - \hat{k}\\\\\\\sf\dashrightarrow\tau\ = \sqrt{(2)^2 + (-2)^2 + (-1)^2} \\\\\\\sf\dashrightarrow\tau\ = \sqrt{4 + 4 +1} \\\\\\\sf\dashrightarrow\tau\ = \sqrt{9}$

$\sf\dashrightarrow\tau\ = 3\;Nm \\\\\bullet\boxed{\bf{Hence,\; the \; required \; answer \;is \; 3\;Nm.}}$

Answer 2

Answer:

hi bro please mark me as BRAINLIEST

Explanation:

it is 3nm