a force F=2i-3j+7k acts on a particle undergoes displacement r=7i+3j-2k.calculate the workdone by the force
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work done = f.s
= (2i x 7i ) + (-3j x 3j ) + ( 7k x -2k)
=14-9-14
=-9 joules
= (2i x 7i ) + (-3j x 3j ) + ( 7k x -2k)
=14-9-14
=-9 joules
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