Question

A force F = (2i +3j)N acts on a particle and displaces it from initial position X = (3i – 4j)m to final position
x2 = (2i + 3j)m, then work done by force, is
(1) -19 J
(2) -25J
(3)12J
(4) 19 J
​

Answer 1

Answer:

19J

Explanation:

Now,

Work done 

W=force×displacement

Given data

force=(i^+j^)

Now, displacement

d=(x2−x1)=(2i^+3j^)−(3i^-4j^)=−i^−j^

w=F×d

W=(2i^+3j^)×(−i^−j^)=−2i^+21j^=19J