Physics, asked by RAWVEDANT, 4 months ago

a force F = (2î + 5j + k)N is acting on a particle. The particle is first displaced from (0,0,0) to (2m,2m,0) along the path x=y and then from (2m,2m,0) to (2m,2m,2m) along the path x=2m , y=2m. The total work done in the complete path is​

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Answered by anmolshukla743
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