Question

A force F = (3 i +40) Newton (where x is in
metres) acts on a particle which moves from a
position (2m, 3m) to (3m, Om). Then the work
done is
(1) 7.5J
(2)-12J
(3) -9J
(4) +4,5 J​

Answer 1

Answer:

-9J

Explanation:

F=3i + 4j

displacement = (3-2)i + (0-3)j

= i-3j

now work done is dot product of f and displacement

3-12

= -9J

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