Question

A force F=3i+4j newton is applied on a body mass 2kg .Calculate the magnitude and direction of the acceleration in the body.

Answer 1

F= 3i+4j Newton's

M = 2 kg

F = Ma

a = F/M = 1.5 i + 2j

|Magnitude of a = |a| = sqr.(1 .5)(1.5)+(2*2) = 2.5

Direction of a is along force F direction

Direction generally notes unit vector of a is vector. a /|a|

=. ( 1/2.5 ) * (1.5 i +2 j)