A force F→ = 3i + 4j newton is applied on a body of mass 2 kg. Calculate the magnitude and direction of the acceleration in the body. In about 40 to 60 words
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Force=3i+4j
mass=2kg
magnitude of force =5N
Formula of force determination is
◆F=ma
=>5=2×a
=>a=5/2
magnitude of the acceleration is 5/2
now for direction
a=3i+4j/2
a=3/2i+2j
mass=2kg
magnitude of force =5N
Formula of force determination is
◆F=ma
=>5=2×a
=>a=5/2
magnitude of the acceleration is 5/2
now for direction
a=3i+4j/2
a=3/2i+2j
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