Question

A force F→

= 3i + 4j newton is applied on a body of mass 2 kg. Calculate the magnitude and

direction of the acceleration in the body.

Answer 1

${\huge{\red{\textbf{Solution}}}}$

Force=3i+4j
mass=2kg

magnitude of force =5N

Formula of force determination is 

◆F=ma

=>5=2×a

=>a=5/2

magnitude of the acceleration is 5/2

now for direction

a=3i+4j/2
a=3/2i+2j

Answer 2

F=ma......
F=3i+4j...,.......given
..a=2(3i+4j)
a=6i+8j
=direction of acc..
=tan@=8/6