a force f 3i+4j newton is applied on a body of mass 2kg calculate the magnitud anf direction of the acceleration in the body
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Hey friend...
Here is your answer...
F=fi^2 +fj^2 +fz^2 in under root
F=4^2 +3^2 in root
F=5N
Acceleration =F/M
=5/2
=2.5 m/s^2
HOPE that it will help you
Plz mark it as brainliest answer
Here is your answer...
F=fi^2 +fj^2 +fz^2 in under root
F=4^2 +3^2 in root
F=5N
Acceleration =F/M
=5/2
=2.5 m/s^2
HOPE that it will help you
Plz mark it as brainliest answer
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