Physics, asked by iqra86788, 4 months ago

A force F = 3i+j - 3k newton moves a
particle from the point (1, 0, 0) to (2, 1, 1) in
metres. The work done in joule is
A - 1
B. 1
C. 2
D. -2​

Answers

Answered by sashikantchoubey
0

Answer:

the displacement vector will be (r) = ( 2 -1) i + ( 1 - 0 ) j + ( 1 - 0)k

therefore r = i + j + k

work = F. r

= ( 3i +j -3k) .( i + j + k)

= 3 + 1 - 3

= 1

Similar questions