A force F = 3i+j - 3k newton moves a
particle from the point (1, 0, 0) to (2, 1, 1) in
metres. The work done in joule is
A - 1
B. 1
C. 2
D. -2
Answers
Answered by
0
Answer:
the displacement vector will be (r) = ( 2 -1) i + ( 1 - 0 ) j + ( 1 - 0)k
therefore r = i + j + k
work = F. r
= ( 3i +j -3k) .( i + j + k)
= 3 + 1 - 3
= 1
Similar questions