Question

A force F = 3t2 (where t is the time) acts on a body of mass
2 kg which is at rest. What is its velocity at t = 2s?​

Answer 1

Answer:-

Given:

Initial Velocity (u) = 0 m/s [ body is at rest ]

Force acting on the body (F) = 3t²

Mass of the body (m) = 2 kg.

We have to find:

Velocity of the body after 2 s [ t = 2 s]

We have:

F = 3t²

Put the value of t as 2.

→ F = 3 * (2)²

→ F = 12 N

We know that,

Force = mass * acceleration

→ 12 = 2 * acceleration (a)

→ a = 12/2

→ a = 6 m/s²

Using 1st equation of motion,

→ v = u + at

(v is the final Velocity - velocity at t = 2 s )

→ v = 0 + 6 * 2

→ v = 12 m/s

Hence, the velocity of the body after 2 seconds is 12 m/s.

Answer 2

Answer:

12 m/s

Explanation:

Given:

Initial Velocity (u) = 0 m/s [ body is at rest ]

Force acting on the body (F) = 3t²

Mass of the body (m) = 2 kg.

To find:

Velocity of the body after 2 s [ t = 2 s]

We have:

F = 3t²

substitute the value of t as 2.

then,

→ F = 3 * (2)²

→ F = 12 N

We know that,

Force = mass * acceleration

as we know,

Force (f) = 12

Mass (m) = 2

Acceleration (a) = ?

now,

→ 12 = 2 * (a)

→ a = 12/2

→ a = 6 m/s²

Using  the 1st equation of motion,

→ v = u + at

( where, v is the final Velocity - velocity at t = 2 s )

→ v = 12 m/s

Therefore, velocity of the body after 2 seconds is 12 m/s.

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