Question

A force F = (3x2+2x–7) N acts on a 2 kg body as
a result of which the body gets displaced from x=0
to x=5m. The work done by the force will be-​

Answer 1

Answer:

Given,

F=(3x2+2x−7)N

m=2kg

From x=0 to x=5m

The work done by the force will be,

dW=F.dx

W=∫05(3x2+2x−7).dx

W=∣33x3+22x2−7x∣05

W=∣x3+x2−7x∣05

W=(5)3+(5)2−7(5)

W=150−35

W=115J

The correct option is C.