Physics, asked by deepakushwanshi, 1 year ago

a force F =(3xi^+4j^) Newton (where x is in metres) acts on a particle which moves from a position (2m,3m) to (3m,0m) .then the work done is
A) 7.5 Joule
B) -12joule
C) -4.5 Joule
D) +4.5 Joule

Answers

Answered by vickeydey

Here we have to USE the concept of line integration.
Then, F=3xi+4j .
Also, ds= dxi+dyj
Hence, dW=F.ds
Then see the attachment.................

Attachments:

deepakushwanshi: but in y component limits are 0 to 3 y r u taking 3 to 0

deepakushwanshi: i ws wrong srry ....

deepakushwanshi: thnku

vickeydey: hm

Answered by shubhangisingh27

its your answers................

Attachments:

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