a force F =(3xi^+4j^) Newton (where x is in metres) acts on a particle which moves from a position (2m,3m) to (3m,0m) .then the work done is
A) 7.5 Joule
B) -12joule
C) -4.5 Joule
D) +4.5 Joule
Answers
Answered by
56
Here we have to USE the concept of line integration.
Then, F=3xi+4j .
Also, ds= dxi+dyj
Hence, dW=F.ds
Then see the attachment.................
Then, F=3xi+4j .
Also, ds= dxi+dyj
Hence, dW=F.ds
Then see the attachment.................
Attachments:
deepakushwanshi:
but in y component limits are 0 to 3 y r u taking 3 to 0
i ws wrong srry ....
thnku
hm
Answered by
21
its your answers................
Attachments:
Similar questions