Question

A force F=4i+3j N acts on a particle for 2s. The magnitude of impulse of the force acting on the particle will be? a:- 20Ns. b:- 2Ns. c:- 10Ns. d:- 5 Ns
It's urgent sorry:(​

Answer 1

Answer:

Ans is C- 10Ns

Explanation:

Impulse is basically magnitude of change of Momentum i.e

J = ΔP = FΔT, where J is the Impulse, F is the force, P the momentum and T is the time. Δ represents change in magnitude.

now in the given question,

F = 4i + 3j N

Calculate the magnitude of the resultant got from the above vector. We need only the magnitude and not direction in this question.

F (resultant) = $\sqrt{4^{2} + 3^{2} }$ = $\sqrt{25}$ = 5 N

Now just use the Impulse Formula J = FΔT = 5 × 2

    = 10 Ns

I hope you got my explanation.