Question

a force F=4i-5j+3k acts at a point r1=i-2j+3k. the torque act about a point R2=3i-2j-3k
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Answer 1

Answer:

Net,r =r2-r1=2i-4j-6k

f =4i-5j+3k

tork =f×r

=(2i-4j-6k) (4i-5j+3k)

=8+20-18

=10 Nm

Step-by-step explanation:

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