Question

A force F=4i+6j+3k acting on a particle produces a displacement of S = 2i+3j+5k where F is expressed in newtom and S in metre .find the work done by the force

Answer 1

Work = Dot product of F and S
= F · S
= (4i + 6j + 3k) · (2i + 3j + 5k)
= 8 + 18 + 15
= 41 Joule

Work done by force is 41 Joule

Answer 2

hey user

work done = F*S ( F.S)

F.S

(4i+6j+3k).(2i+3j+5k)

4×2(1)+6×3(1)+3×5(1).

8+18+15

41.

therefore, work done= 41 joules.

hope this helps ❤