Question

A force F = 5 + 0.5x acts on a particle in X direction where F is in N and x is in m. The work done by this force during a displacement from x = 0 to x = 1 m is​

Answer 1

Answer:

10.5 J

Explanation:

We are given that force acting on a particle in the x- direction is given by,

F=5+0.5x,

Where F ( in N) and x(in meters) ,

We have to find the work done by the force during a displacement from x=0 to x=1 m ,

We know that work done =f dx,

W=∫²0(5+0.5x)dx,

W=[5x+0.5x²/1]²0,

W=5(2)+0.5/2(1)²-5(0)-0.5/2(0)²,

∫ba∫dx=F(b)-F(a),

W=10+0.5,

W=10.5,

Hence, the work done by the force=10.5J.

Hope it helps

Answer 2

Answer:

10.5j....................